📖 ContentsChapter 10
Genetics · Chapter 10

Molecular Genetic Tools and Genomics

Fifty years ago no one could read a gene, copy it in a test tube or change a single chosen base in a living cell. Today a student can amplify DNA from a drop of saliva in an afternoon, sequence a whole human genome in a day and edit a gene with a programmable enzyme borrowed from bacteria. This chapter explains the tools that made genetics a molecular science and the genomic thinking they made possible.

By the end of this chapter you can

  • Explain how restriction enzymes, DNA ligase and plasmid vectors are used to clone DNA, and calculate expected restriction site frequencies.
  • Describe the steps of the polymerase chain reaction and calculate product yield and relative expression by qPCR.
  • Read a Sanger sequencing result and contrast it with short read and long read sequencing.
  • Calculate sequencing coverage and explain why repeats make genome assembly difficult.
  • Design a CRISPR-Cas9 guide next to a PAM and predict the outcomes of NHEJ and HDR repair.
  • Compare nuclease editing with base editing, prime editing and CRISPR interference.
  • Describe how genome sequence is annotated and what fraction of the human genome is coding, regulatory and repetitive.
  • Interpret RNA-seq fold changes, distinguish orthologs from paralogs, and use dN/dS to infer selection.

Section 1Restriction enzymes, cloning and PCR

Restriction enzymes: molecular scissors

Bacteria defend themselves against viruses with restriction-modification systems. A restriction endonuclease cuts DNA at a specific recognition sequence, and a partner methyltransferase methylates the same sequence in the host's own DNA so that it is protected. Invading phage DNA, lacking the methyl marks, is cut. The type II enzymes used in the lab cut within or right next to their recognition site, which is usually 4 to 8 bp long and palindromic: it reads the same 5′ to 3′ on both strands. EcoRI recognizes 5′-GAATTC-3′, whose complement read 5′ to 3′ is also GAATTC.

Enzymes leave three kinds of ends:

EnzymeSite (cut marked ^)End producedSource organism
EcoRIG^AATTC4 nt 5′ overhang (sticky)Escherichia coli
BamHIG^GATCC4 nt 5′ overhang (sticky)Bacillus amyloliquefaciens
PstICTGCA^G4 nt 3′ overhang (sticky)Providencia stuartii
SmaICCC^GGGBluntSerratia marcescens
AluIAG^CTBlunt; 4 bp site cuts oftenArthrobacter luteus

Sticky ends are single stranded overhangs that base pair with any other end made by the same enzyme. When a vector and an insert are cut with the same enzyme, their ends anneal, and DNA ligase seals the sugar-phosphate backbone by forming phosphodiester bonds. Cutting with two different enzymes gives incompatible ends at either side, which forces the insert to enter in one orientation (directional cloning). Blunt ends can be joined to any other blunt end, but less efficiently.

If bases were random and equally frequent, a given 4 bp site would occur on average once every 44 = 256 bp, a 6 bp site once every 46 = 4,096 bp and an 8 bp site once every 48 = 65,536 bp. Real genomes deviate (CpG containing sites are rare in mammals), but the estimate is useful. Fragments are separated by gel electrophoresis: DNA is negatively charged, so it migrates toward the positive electrode, and smaller fragments move faster through the agarose mesh. Distance traveled is roughly proportional to the logarithm of size, so sizes are read against a ladder of known fragments.

Study tip. Worked problem: (a) About how many EcoRI sites are expected in the 4.6 Mb E. coli genome? (b) A 10 kb linear fragment cut with EcoRI gives 3 kb and 7 kb pieces; with BamHI, 4 kb and 6 kb; with both, 3, 1 and 6 kb. Map the sites.
Step 1 (a): A 6 bp site occurs once every 46 = 4,096 bp. 4,600,000 ÷ 4,096 = 1,123, so about 1,100 sites.
Step 2 (b): Put EcoRI 3 kb from the left end. BamHI is either 4 kb or 6 kb from the left end.
Step 3: Test BamHI at 4 kb. Double digest pieces: 0 to 3 (3 kb), 3 to 4 (1 kb), 4 to 10 (6 kb). This matches 3, 1, 6.
Step 4: Test BamHI at 6 kb. Pieces: 3, 3 and 4 kb. This does not match.
Answer: (a) about 1,100 sites; (b) EcoRI at 3 kb and BamHI at 4 kb from the same end, 1 kb apart. Always check sums: 3 + 1 + 6 = 10 kb, the full fragment.

Vectors and cloning

A vector carries a DNA fragment into a host cell and replicates it there. A typical plasmid cloning vector has an origin of replication, a selectable marker such as an ampicillin resistance gene so that only cells that took up the plasmid survive, and a multiple cloning site (polylinker) containing many unique restriction sites. In many vectors the cloning site lies within the lacZα fragment. Cells carrying an empty vector make functional β-galactosidase and form blue colonies on X-gal; an insert disrupts lacZα, giving white colonies (blue-white screening). Plasmids are introduced into bacteria by transformation using chemically treated cells or a brief electric pulse.

Plasmids carry inserts up to about 10 to 15 kb. Larger fragments need other vectors: bacteriophage lambda (about 20 kb), cosmids (about 45 kb), bacterial artificial chromosomes (BACs, 100 to 300 kb) and yeast artificial chromosomes (up to 1 Mb or more). Expression vectors add a strong regulated promoter, such as a lac derived promoter induced by IPTG, so the cloned gene's protein can be produced.

Eukaryotic genes contain introns that bacteria cannot remove, so to express a human protein in bacteria researchers clone complementary DNA (cDNA). Retroviral reverse transcriptase copies mature mRNA, primed from its poly(A) tail with oligo(dT), into DNA. A collection of clones representing all mRNAs in a tissue is a cDNA library; one representing all of an organism's DNA is a genomic library.

1. Cut with EcoRI 5' ..G AATTC.. 3' 3' ..CTTAA G.. 5' Staggered cut leaves 5'-AATT overhangs 2. Anneal and ligate Insert sticky ends pair ligase seals nicks Cut vector opened atEcoRI site insert ampR gene ori Recombinant plasmid
Figure 10.1 Cloning with a restriction enzyme. EcoRI makes a staggered cut at GAATTC, leaving complementary AATT overhangs on both insert and vector. After annealing, ligase seals the backbone. The origin (ori) lets the plasmid replicate and the ampicillin resistance gene selects for cells that carry it.

The polymerase chain reaction

Invented by Kary Mullis in the 1980s, the polymerase chain reaction (PCR) copies a chosen segment of DNA billions of times in a few hours without cloning. A reaction contains template DNA, two primers (short single stranded oligonucleotides, usually 18 to 25 nt) complementary to opposite strands at the two ends of the target, the four dNTPs, Mg2+ and a heat stable DNA polymerase, classically Taq polymerase from the hot spring bacterium Thermus aquaticus. Each cycle has three steps:

  1. Denaturation at about 94 to 98 °C separates the strands.
  2. Annealing at about 50 to 65 °C, set a few degrees below the primers' melting temperature, lets primers pair with their sites.
  3. Extension at 72 °C, the optimum for Taq, lets polymerase add nucleotides to each primer's 3′ end, at roughly 1 kb per minute.

Because each new strand can serve as a template in the next cycle, the number of target copies ideally doubles each cycle: after n cycles, N = N0 × 2n. Products of exactly the length between the primers appear in cycle 3 and soon dominate. Amplification slows after about 30 to 35 cycles as primers and dNTPs run low. Taq lacks proofreading and makes roughly one error per 104 to 105 bases, so high fidelity proofreading polymerases are used when sequence accuracy matters. PCR is so sensitive that a single contaminating molecule can be amplified, so careful technique and negative controls are essential.

Denature 95 °CAnneal ~55 °CExtend 72 °C Strands separate Primers bind (red),3' ends point inward Polymerase copies;two duplexes now Copies double each cycle: N = N0 × 2n start: 1cycle 1: 2cycle 2: 4cycle 3: 8 cycle 30:about 109
Figure 10.2 The polymerase chain reaction. Each cycle of denaturation, annealing and extension ideally doubles the number of target molecules, so 30 cycles turn one molecule into about a billion copies.

Variations: RT-PCR and quantitative PCR

RT-PCR starts with reverse transcription of RNA into cDNA, then amplifies it, to detect transcripts or RNA viruses. Quantitative (real time) PCR (qPCR) follows product accumulation each cycle with a fluorescent dye or probe. The threshold cycle (Ct) is the cycle at which fluorescence crosses a set threshold; the more starting template, the earlier this happens. Each cycle earlier means twice as much template. Relative expression is usually calculated by the ΔΔCt method, which normalizes the target gene to a stable reference gene in each sample.

Study tip. Worked problem: (a) A PCR begins with 100 copies of a target. How many copies after 30 perfect cycles? (b) In qPCR, the target gene has Ct 27.0 in control cells and 24.5 in drug treated cells; the reference gene has Ct 18.0 in control and 18.5 in treated. What is the fold change in target expression?
Step 1 (a): N = 100 × 230 = 100 × 1,073,741,824 = about 1.07 × 1011 copies.
Step 2 (b): Normalize each sample: ΔCt = Ct(target) − Ct(reference). Control: 27.0 − 18.0 = 9.0. Treated: 24.5 − 18.5 = 6.0.
Step 3: ΔΔCt = ΔCt(treated) − ΔCt(control) = 6.0 − 9.0 = −3.0.
Step 4: Fold change = 2−ΔΔCt = 23 = 8.
Answer: (a) about 1.1 × 1011 copies; (b) the drug raises target expression eightfold. Note that the raw Ct difference (2.5 cycles) would have underestimated the change, because the treated sample was loaded with slightly less RNA.
Connection. PCR is everywhere in medicine and law. RT-qPCR became the reference test for SARS-CoV-2 infection, detecting viral RNA in a nasal swab. Forensic DNA profiles amplify about 20 short tandem repeat loci in one multiplex reaction; because each locus has many length alleles, the chance that two unrelated people share a full profile is typically below one in a billion billion.
Key point

Type II restriction enzymes cut palindromic sites into sticky or blunt ends that ligase can join, letting DNA be cloned into vectors with an origin, a selectable marker and a cloning site. A random n base site occurs once per 4n bp. PCR doubles a target each cycle of denaturing, annealing and extending; qPCR measures template amount from the threshold cycle, with fold change equal to 2−ΔΔCt.

Section 2Sequencing technologies

Sanger chain termination sequencing

In 1977 Frederick Sanger introduced the method that would dominate sequencing for thirty years. It exploits dideoxynucleotides (ddNTPs), which lack the 3′ hydroxyl group that DNA polymerase needs to attach the next nucleotide. A reaction contains a single stranded template, one primer, DNA polymerase, the four normal dNTPs and a small amount of the four ddNTPs. Each time polymerase happens to add a ddNTP instead of the matching dNTP, the strand stops growing. The result is a nested set of fragments, each beginning at the primer and ending at a particular position with a ddNTP that identifies the base there.

In the original method four separate reactions, one per ddNTP, were run in adjacent lanes of a gel. In modern automated sequencing each ddNTP carries a different colored fluorescent dye, so one reaction suffices; the fragments are separated by size in a thin capillary, and a laser reads the color of each fragment as it passes the detector. Fragments emerge from shortest to longest, so the sequence is read in the 5′ to 3′ direction of the newly synthesized strand, which is complementary to the template. A single Sanger read covers about 700 to 1,000 bases with very high accuracy (about 99.99 percent), so Sanger sequencing remains the standard for confirming a single mutation or checking a cloned insert.

Study tip. Worked problem: Sanger fragments (lengths in nucleotides beyond the primer) end in ddA at 3 and 7; ddC at 1, 5 and 8; ddG at 2, 6 and 10; ddT at 4 and 9. What is the sequence of the new strand and of the template?
Step 1: List the fragments in order of size with their terminal base: 1 C, 2 G, 3 A, 4 T, 5 C, 6 G, 7 A, 8 C, 9 T, 10 G.
Step 2: The shortest fragment ends nearest the primer, so this order is the new strand read 5′ to 3′: 5′-CGATCGACTG-3′.
Step 3: The template is complementary and antiparallel. Complement: GCTAGCTGAC, which runs 3′ to 5′. Written 5′ to 3′: 5′-CAGTCGATCG-3′.
Answer: new strand 5′-CGATCGACTG-3′; template 5′-CAGTCGATCG-3′. The usual mistake is reporting the new strand as the template.
Nested fragments from the primer template 3'-GCTAGCTGAC-5' ends ddC (1)ends ddG (2)ends ddA (3)ends ddT (4) ... primer Each ddNTP lacks a 3' OH, so the chain stops where it is added. Capillary readout CGATCGACTG short fragments first, read 5' to 3' New strand: 5'-CGATCGACTG-3' Template: 5'-CAGTCGATCG-3' (reverse complement) C blue, G black, A green, T red
Figure 10.3 Sanger chain termination sequencing. Dye labeled ddNTPs stop synthesis at each position, producing nested fragments. Read from shortest to longest, the peaks give the new strand 5′ to 3′; the template is its reverse complement.

Short read sequencing by synthesis

The Human Genome Project, completed in 2003 at a cost of about three billion dollars, relied on Sanger sequencing. Massively parallel (next generation) methods introduced after 2005 cut the cost of a human genome to a few hundred dollars by sequencing hundreds of millions of fragments at once. The most widely used approach is sequencing by synthesis with reversible terminators:

  1. Library preparation. Genomic DNA is fragmented to a few hundred base pairs and short adapters are ligated to both ends.
  2. Cluster amplification. Fragments bind to a glass flow cell coated with oligonucleotides matching the adapters and are copied in place by bridge amplification, producing clusters of about a thousand identical copies.
  3. Sequencing. Each cycle, polymerase adds one fluorescent nucleotide whose 3′ end is reversibly blocked. A camera records the color of every cluster, the dye and block are removed, and the cycle repeats.

Reads are short, typically 100 to 300 bases, and are often paired end (both ends of each fragment are read), which helps place them. Per base accuracy is about 99.9 percent. Short reads are ideal for resequencing, where reads are aligned to a reference genome to find variants, and for counting molecules, as in RNA-seq.

Long read sequencing

Two technologies read single molecules thousands of bases long. In single molecule real time sequencing, one polymerase sits at the bottom of a tiny well and the flash of each fluorescent nucleotide is recorded as it is incorporated. In nanopore sequencing, a single DNA strand is pulled through a protein pore in a membrane, and the change in ionic current reveals the bases in the pore; reads can exceed 100 kb, and modified bases such as 5-methylcytosine can be detected directly. Raw error rates were once high but repeated reading of the same molecule now gives accuracy above 99.9 percent.

MethodRead lengthStrengthsLimitations
Sanger700 to 1,000 basesVery accurate; simple for one targetLow throughput, costly per base
Short read sequencing by synthesis100 to 300 bases, pairedHuge throughput, cheapest per baseCannot span long repeats or resolve complex structure
Single molecule real time10 to 25 kb, highly accurateResolves repeats and haplotypesHigher cost per base
NanoporeTens of kb to over 1 MbLongest reads, portable, reads base modificationsSomewhat higher error in some contexts

Coverage and assembly

Because fragments are sampled randomly, some positions are read many times and others not at all. Coverage (depth) is the average number of reads covering a base: C = L × N ÷ G, where L is read length, N the number of reads and G genome size. If reads land at random, the number covering a given base follows a Poisson distribution, so the fraction of bases with zero coverage is about e−C (the Lander-Waterman estimate). Clinical genome sequencing typically aims for 30x or more so that both alleles at a heterozygous site are sampled many times.

Putting reads back together into a genome is assembly. De novo assembly builds the genome from overlaps among reads alone, producing contigs (continuous sequences) that are linked into scaffolds using paired reads or long reads. Reference based assembly aligns reads to an existing genome of the same species. The great obstacle is repeats: if a repeated element is longer than the reads, the assembler cannot tell which copy a read came from, and the assembly breaks. This is why the first human reference left roughly 8 percent of the genome, mostly centromeres and other long repeats, unfinished until long reads produced the first complete, telomere to telomere human sequence in 2022.

Study tip. Worked problem: A 3.1 Gb human genome is sequenced with 600 million reads of 150 bases. (a) What is the average coverage? (b) If instead coverage were only 5x, about how many bases would have no reads?
Step 1 (a): C = L × N ÷ G = 150 × 600,000,000 ÷ 3,100,000,000 = 90,000,000,000 ÷ 3,100,000,000 = 29.0, about 29x.
Step 2 (b): Fraction uncovered = e−5 = 0.0067.
Step 3: Bases uncovered = 0.0067 × 3,100,000,000 = about 20.9 million bases.
Answer: about 29x coverage; at 5x, roughly 21 Mb (0.67 percent) would be missed entirely, and many more bases would have too few reads to call both alleles. Real coverage is less even than Poisson, so the true gap is larger.
Key point

Sanger sequencing uses ddNTPs lacking a 3′ OH to make nested fragments read from shortest to longest as the new strand. Massively parallel short read sequencing gives enormous, cheap output of 100 to 300 base reads; long read methods span repeats and detect base modifications. Coverage C = LN/G, and the fraction of bases missed is about e−C. Repeats longer than reads are the main barrier to assembly.

Section 3CRISPR and genome editing

From bacterial immunity to a programmable tool

Many bacteria and most archaea carry CRISPR arrays (clustered regularly interspaced short palindromic repeats): short repeats separated by unique spacers, many of which match sequences from viruses and plasmids. Nearby lie cas (CRISPR associated) genes. Together they form an adaptive immune system. When a cell survives infection, Cas proteins snip a piece of the invader's DNA and insert it as a new spacer at the front of the array, a heritable record of the encounter. The array is transcribed and processed into short CRISPR RNAs (crRNAs), each carrying one spacer. A crRNA guides Cas nucleases to destroy any matching DNA that enters later.

In 2012 Jennifer Doudna and Emmanuelle Charpentier showed that the Cas9 nuclease of Streptococcus pyogenes could be directed to cut any chosen DNA sequence in a test tube using a guide RNA, and within months others showed it worked in human cells. Earlier engineered nucleases, zinc finger nucleases and TALENs, recognized DNA through custom built proteins, which had to be redesigned for every target. Cas9 is retargeted simply by changing 20 nucleotides of RNA.

How Cas9 finds and cuts its target

In the lab, the natural crRNA and its partner tracrRNA are fused into a single guide RNA (sgRNA) of about 100 nucleotides. Its first 20 nucleotides, the spacer, match the target. Cas9 first scans DNA for a short protospacer adjacent motif (PAM), which for S. pyogenes Cas9 is 5′-NGG-3′ (N is any base). On finding a PAM, Cas9 unwinds the adjacent DNA and tests whether the guide pairs with it. If the 20 nt protospacer immediately 5′ of the PAM matches the guide, the two nuclease domains of Cas9 (HNH and RuvC) each cut one strand, producing a blunt double strand break 3 bp upstream of the PAM. The PAM requirement is how bacteria avoid cutting their own CRISPR arrays, which contain the spacer but not the PAM. Mismatches near the PAM, in the so called seed region of the guide, block cutting more than mismatches far from it.

Cas9 non-target strand target strand NGG 20 nt protospacer guide pairs with target blunt cut 3 bp from PAM NHEJ (no template) Ends rejoined directly Small insertions or deletions Frameshift: gene knockout indel HDR (donor template) Donor with homology arms copied across the break Precise edit or insertion
Figure 10.4 Cas9 targeting and repair. The guide RNA pairs with the target strand of a 20 bp protospacer that lies immediately 5′ of an NGG PAM on the non-target strand, and Cas9 cuts both strands 3 bp upstream of the PAM. Nonhomologous end joining leaves indels; homology directed repair copies a supplied donor.
Study tip. Worked problem: Design an SpCas9 guide that targets this strand and predict the cut site: 5′-GATCCTGAACGTTAGCATGGCAACCTTGAGCGTTACCGGAATTCGA-3′ (46 nt).
Step 1: Search the strand for NGG. Positions 37 to 39 read CGG (numbering from the 5′ end), the only NGG with 20 bases upstream on this strand.
Step 2: The protospacer is the 20 nt immediately 5′ of the PAM, positions 17 to 36: ATGGCAACCTTGAGCGTTAC.
Step 3: The guide spacer has the same sequence as the protospacer, written in RNA: 5′-AUGGCAACCUUGAGCGUUAC-3′. It pairs with the opposite (target) strand. Do not include the PAM in the guide.
Step 4: Cas9 cuts 3 bp upstream of the PAM, between protospacer nucleotides 17 and 18, which are positions 33 and 34: ...GAGCGTT^ACCGG...
Answer: guide 5′-AUGGCAACCUUGAGCGUUAC-3′; blunt cut between T33 and A34. If NHEJ leaves a random small indel, about two thirds of indels shift the reading frame (any length not divisible by 3), which usually knocks out the gene.

Repairing the break: knockouts and knock-ins

Cas9 only cuts; the cell's own repair pathways decide the outcome. Nonhomologous end joining (NHEJ) rejoins the broken ends directly and often adds or removes a few bases. Because the edited site is still a target, cutting and repair repeat until an indel destroys the site. In a coding exon, frameshifting indels create premature stop codons and usually a knockout. Homology directed repair (HDR) uses a template with sequence matching both sides of the break; if researchers supply a donor DNA carrying a desired change between homology arms, the cell copies it in, giving a precise knock-in. HDR is active mainly in dividing cells in S and G2 and is less efficient than NHEJ.

Beyond cutting

ToolComponentsWhat it does
Cas9 nucleaseCas9 + sgRNADouble strand break; knockout by NHEJ or knock-in by HDR
Cytosine base editorCas9 nickase fused to a cytidine deaminaseConverts C•G to T•A in a small window without a double strand break
Adenine base editorCas9 nickase fused to an engineered adenosine deaminaseConverts A•T to G•C
Prime editorCas9 nickase fused to reverse transcriptase + pegRNAWrites any small substitution, insertion or deletion encoded in the guide's extension
CRISPRi and CRISPRaCatalytically dead Cas9 (dCas9) fused to a repressor or activator domainTurns transcription down or up without changing DNA
Cas12aSingle crRNA; T rich PAM (TTTV)Staggered cut; processes its own guide arrays
Cas13RNA guided RNaseCleaves RNA; used for knockdown and diagnostics

CRISPR is also used as a screening tool: libraries of tens of thousands of guides, one or more per gene, are delivered to a population of cells, which are then selected (for example, for drug resistance), and sequencing the guides in survivors reveals which gene knockouts matter. In agriculture, editing has produced disease resistant and nonbrowning crops. A gene drive places the Cas9 and guide genes inside the target site itself, so a heterozygote converts its wild type allele and passes the drive to nearly all offspring; drives are being tested to suppress malaria carrying mosquitoes.

Editing raises safety and ethical issues. Off target cutting at similar sequences, large deletions at the target, and mosaicism when editing happens after the first cell division are technical risks. Editing of somatic cells affects only the patient, whereas germline editing of embryos would be inherited. When edited babies were announced in 2018, the work was widely condemned as unsafe and unjustified, and most countries restrict heritable editing.

Connection. The first approved CRISPR therapy, for sickle cell disease and transfusion dependent β thalassemia, edits a patient's own blood stem cells outside the body. Cas9 disrupts the erythroid enhancer of BCL11A, a repressor of fetal hemoglobin (Chapter 9). The edited cells are returned after chemotherapy, make high levels of fetal hemoglobin, and in trials most patients became free of pain crises or transfusions.
Key point

CRISPR began as bacterial adaptive immunity. SpCas9, guided by a 20 nt spacer, cuts both strands 3 bp upstream of an NGG PAM. NHEJ repair leaves indels that knock out genes; HDR with a donor makes precise changes. Base editors, prime editors and dCas9 fusions change bases or expression without double strand breaks, while off target effects and germline editing remain major concerns.

Section 4Genome structure and annotation

Genome size and gene number

Genomes vary enormously in size, but the number of genes varies much less, and neither tracks organismal complexity well. The lack of correlation between genome size (the C-value, the DNA content of a haploid genome) and complexity is called the C-value paradox. Some amoebae, lungfish and lilies have genomes many times larger than ours. The paradox is resolved by noncoding DNA: genome size differences come mostly from repetitive sequences and transposable elements, not from extra genes.

OrganismGenome sizeProtein coding genes (approx.)Note
Escherichia coli4.6 Mb4,300About 88 percent coding; few introns
Saccharomyces cerevisiae (yeast)12 Mb6,000Compact; few introns
Caenorhabditis elegans100 Mb20,000First animal genome sequenced (1998)
Drosophila melanogaster140 Mb14,000Fewer genes than a worm
Arabidopsis thaliana135 Mb27,000Model plant with a small genome
Homo sapiens3.1 Gb20,000About 1.5 percent protein coding
Wheat (bread)About 16 GbAbout 100,000Hexaploid; mostly repeats

In bacteria, genes are packed densely, with about one gene per kilobase and short intergenic spacers. In humans, the average protein coding gene spans about 27 kb, but its mature mRNA is only about 3 kb, because most of the gene is introns; the average gene has about 9 exons. Only about 1.5 percent of the human genome encodes protein. Roughly another 5 to 10 percent is under evolutionary constraint, including regulatory elements and noncoding RNA genes. Humans also have about 20,000 noncoding RNA genes, including those for rRNA, tRNA, snRNA, microRNAs and long noncoding RNAs.

Repetitive DNA and transposable elements

About half of the human genome consists of transposable elements, sequences that move or once moved within the genome (Chapter 7), almost all of them now inactive.

Other repeats include satellite DNA (tandem arrays at centromeres, such as the 171 bp alpha satellite), minisatellites and microsatellites (short tandem repeats used in forensic profiling), and segmental duplications, long blocks over 1 kb with more than 90 percent identity that make up about 5 percent of the genome and promote rearrangements by unequal crossing over. Gene families arise by duplication, and many duplicates decay into pseudogenes; processed pseudogenes, lacking introns and ending in a poly(A) stretch, are mRNA copies reinserted by LINE reverse transcriptase.

Annotation: finding the genes

A raw genome sequence is a string of letters. Annotation identifies the genes and other functional elements in it. Structural annotation marks where genes, exons, introns, UTRs and regulatory elements lie; functional annotation assigns probable roles, usually by similarity to known proteins and domains.

The simplest clue to a protein coding gene is an open reading frame (ORF): a stretch beginning with a start codon (ATG) and continuing without a stop codon (TAA, TAG or TGA). Each double stranded sequence has six possible reading frames, three on each strand. In random sequence, 3 of the 64 codons are stops, so stops occur on average every 64 ÷ 3 = 21 codons. A long ORF is therefore unlikely by chance and strongly suggests a real gene. In bacteria, finding long ORFs and a ribosome binding site upstream identifies most genes. In eukaryotes, introns break ORFs into pieces, so gene finding programs combine several kinds of evidence:

Annotation also uses CpG islands, chromatin marks such as H3K4me3 at promoters and H3K27ac at enhancers (Chapter 9), and DNase or ATAC accessibility. The project that mapped these features across many human cell types concluded that a large fraction of the genome shows some biochemical activity, though how much of that activity matters for fitness is debated; evolutionary constraint suggests that under 10 percent is functional in that stricter sense.

Gene modelRNA-seq readsConservation enhancer promoter, TSS intron 1 (GU...AG)intron 2 ATGstop 5' UTR 3' UTR split reads span introns peaks over coding exons and the enhancer
Figure 10.5 Combining evidence to annotate a gene. The gene model (exons dark blue, UTRs light blue) is supported by RNA-seq reads that pile up on exons and split across introns, and by cross species conservation that peaks over coding exons and an upstream enhancer.
Study tip. Worked problem: (a) In random sequence with equal base frequencies, what is the probability that a 100 codon stretch in one reading frame contains no stop codon? (b) A bacterial genome of 5.0 Mb contains 4,700 annotated genes averaging 950 bp. What fraction is coding?
Step 1 (a): The chance a random codon is not a stop is 61 ÷ 64 = 0.953. For 100 independent codons: 0.953100. Using logs: 100 × ln(0.953) = 100 × (−0.0480) = −4.80, and e−4.80 = 0.0082.
Step 2: So only about 0.8 percent of random 100 codon stretches in a given frame are stop free. A 300 codon ORF would arise by chance with probability about (0.953)300 = 5.6 × 10−7.
Step 3 (b): Coding DNA = 4,700 × 950 = 4,465,000 bp. Fraction = 4,465,000 ÷ 5,000,000 = 0.893.
Answer: (a) about 0.008, which is why long ORFs flag real genes; (b) about 89 percent coding, typical of bacteria and in sharp contrast to about 1.5 percent in humans.

Organelle genomes

Mitochondria and chloroplasts carry their own small circular genomes, relics of their bacterial ancestors. Human mitochondrial DNA is 16,569 bp and encodes 37 genes: 13 proteins of the respiratory chain, 22 tRNAs and 2 rRNAs. It has almost no noncoding DNA apart from the control region (D-loop), is present in hundreds to thousands of copies per cell and is maternally inherited. Most mitochondrial proteins, more than a thousand, are encoded in the nucleus and imported, showing that genes have moved from the organelle to the nucleus over evolutionary time.

Key point

Genome size reflects mostly repeats, not gene number (the C-value paradox). Only about 1.5 percent of the human genome codes for protein, about half is transposable element sequence, and genes are long because of introns. Annotation combines ORFs (long ORFs are improbable by chance), splice signals, transcript evidence and conservation.

Section 5Functional and comparative genomics

From sequence to function

Functional genomics asks what all the genes and elements of a genome do, on a genome wide scale. Two broad strategies exist. Forward genetics starts from a phenotype, such as a mutant that cannot grow on lactose, and finds the responsible gene. Reverse genetics starts from a gene sequence and disrupts it, with knockouts, RNAi or CRISPR, to see what phenotype results. Genome wide versions of reverse genetics include collections of yeast strains with every gene deleted and pooled CRISPR screens in human cells. Such screens show, for example, that only about 1,000 of yeast's 6,000 genes are essential in rich medium, and that about 2,000 human genes are essential for growth of a typical cell line.

Measuring the transcriptome and more

The transcriptome is the set of RNAs present in a sample. RNA-seq converts RNA to cDNA, sequences it, and maps reads to the genome; the number of reads per gene estimates its expression. Because samples are sequenced to different depths and genes differ in length, counts are normalized, for example as counts per million (CPM) or transcripts per million (TPM), which also corrects for length. Changes are usually reported as log2 fold change, so that a doubling is +1, a halving is −1 and no change is 0. Statistical tests across biological replicates determine whether a change is significant, and the large number of genes tested requires correction for multiple comparisons. Single cell RNA-seq profiles thousands of individual cells and has revealed new cell types in many tissues. Older microarrays measured hybridization of labeled cDNA to probes on a chip.

MethodWhat it measuresTypical question
RNA-seqAbundance of every transcriptWhich genes change after treatment?
Single cell RNA-seqTranscripts in individual cellsWhat cell types are in this tissue?
ChIP-seqGenomic sites bound by a protein or carrying a histone markWhere does this transcription factor bind?
ATAC-seqOpen, accessible chromatinWhich enhancers are active in this cell type?
Mass spectrometry proteomicsProtein identity and abundanceDoes the mRNA change reach the protein level?
Pooled CRISPR screenEffect of knocking out each gene on a selected traitWhich genes are needed for drug resistance?

Other genome wide methods map where proteins bind and which regions are open. ChIP-seq (chromatin immunoprecipitation followed by sequencing) uses an antibody to pull down a transcription factor or histone mark with its bound DNA. ATAC-seq uses a transposase that inserts adapters preferentially into open chromatin, mapping accessible regulatory elements. Proteomics identifies and quantifies proteins by mass spectrometry. Combining these layers lets researchers trace how a variant in an enhancer changes chromatin, transcription and finally protein levels.

Study tip. Worked problem: In RNA-seq, gene X has 500 reads in a control library of 20 million reads and 1,800 reads in a treated library of 30 million reads. What are the CPM values and the log2 fold change?
Step 1: CPM = reads ÷ total reads in millions. Control: 500 ÷ 20 = 25 CPM. Treated: 1,800 ÷ 30 = 60 CPM.
Step 2: Fold change = 60 ÷ 25 = 2.4.
Step 3: log2(2.4) = ln(2.4) ÷ ln(2) = 0.875 ÷ 0.693 = 1.26.
Answer: 25 and 60 CPM; a 2.4 fold increase, log2 fold change of 1.26. Comparing raw counts (1,800 ÷ 500 = 3.6) would have overstated the change because the treated library was sequenced more deeply.

Comparative genomics: homologs, orthologs and paralogs

Comparative genomics compares genomes across species to infer function and evolutionary history. Genes related by common descent are homologs. Homologs come in two kinds that students often confuse:

Synteny, the conservation of gene order on chromosomes, helps identify true orthologs and reveals rearrangements: large blocks of human chromosomes correspond to blocks of mouse chromosomes with their genes in the same order. Sequence conservation outside genes points to function. Some ultraconserved elements are identical over 200 bp or more between human, mouse and rat, and many act as developmental enhancers.

Ancestral globin gene duplication speciation speciation Human α Mouse α Human β Mouse β orthologs paralogs Human α and mouse β: also paralogs
Figure 10.6 Orthologs and paralogs. A duplication (red) in an ancestral genome created the α and β globin lineages; a later speciation (blue) separated human and mouse. Genes whose last common ancestor is a speciation node are orthologs; genes whose last common ancestor is a duplication node are paralogs.

Reading selection from sequence: dN/dS

Comparing coding sequences of orthologs reveals what kind of selection has acted. Substitutions are divided into synonymous (silent, not changing the amino acid) and nonsynonymous (changing it). dS is the number of synonymous substitutions per synonymous site, and dN the number of nonsynonymous substitutions per nonsynonymous site. Because synonymous changes are nearly neutral, dS approximates the neutral rate. The ratio ω = dN/dS then indicates selection on the protein: ω < 1 means purifying selection removed most amino acid changes (the usual case); ω ≈ 1 suggests neutral evolution, as in pseudogenes; ω > 1 indicates positive selection favoring amino acid change, as in some immune and reproductive genes.

Study tip. Worked problem: Two orthologous genes are aligned. There are 300 nonsynonymous sites with 6 nonsynonymous differences and 100 synonymous sites with 10 synonymous differences. Calculate ω and interpret it. (Ignore multiple hits, reasonable for small distances.)
Step 1: dN = 6 ÷ 300 = 0.020.
Step 2: dS = 10 ÷ 100 = 0.100.
Step 3: ω = 0.020 ÷ 0.100 = 0.20.
Answer: ω = 0.2, well below 1. About 80 percent of amino acid changes that would otherwise have accumulated were removed by purifying selection, so this protein is functionally constrained. Note that counting raw differences (6 versus 10) without dividing by the number of sites of each kind would give a misleading 0.6.

Genomes of populations and communities

Sequencing many individuals of a species reveals variation. Population projects have catalogued hundreds of millions of human single nucleotide variants, most rare, which underpin association studies (Chapter 11) and clinical interpretation of variants. A species' pangenome includes genes present in some individuals but not others; in bacteria the variable portion can be larger than the shared core. Metagenomics sequences DNA directly from environmental samples, such as soil, seawater or the human gut, identifying organisms that cannot be cultured and showing that the gut microbiome carries far more genes than the human genome.

Connection. Exome and genome sequencing now diagnose many children with suspected genetic disorders after years of inconclusive testing. Rapid genome sequencing in newborn intensive care units can return results within days, and finding a variant in a known disease gene can change treatment immediately. Interpretation relies on population databases (is the variant too common to cause a rare disease?), conservation and dN/dS-style constraint (does this gene tolerate change?), and functional genomic data.
Key point

Functional genomics measures what genes do on a genome wide scale: forward and reverse genetic screens, RNA-seq with normalized counts and log2 fold changes, ChIP-seq, ATAC-seq and proteomics. Comparative genomics separates orthologs (split by speciation) from paralogs (split by duplication), uses synteny and conservation to find function, and uses ω = dN/dS to detect purifying (ω < 1) or positive (ω > 1) selection.

The chapter in one breath

  • Restriction enzymes cut palindromic sites into sticky or blunt ends; a random n base site appears once per 4n bp.
  • Ligase joins fragments into vectors carrying an origin, a selectable marker and a cloning site; cDNA copies mRNA without introns.
  • PCR doubles its target each cycle; qPCR fold change equals 2−ΔΔCt.
  • Sanger sequencing uses ddNTPs to make nested fragments read from shortest to longest as the new strand.
  • Short reads give massive throughput; long reads span repeats and detect base modifications.
  • Coverage C = LN/G, and about e−C of bases are missed.
  • Cas9 cuts 3 bp upstream of an NGG PAM under a 20 nt guide; NHEJ gives indels and HDR precise edits.
  • Base editors, prime editors and dCas9 fusions change bases or expression without double strand breaks.
  • About 1.5 percent of the human genome is protein coding and about half is transposable elements.
  • Annotation combines long ORFs, splice signals, RNA-seq and conservation.
  • Orthologs arise by speciation, paralogs by duplication, and dN/dS below 1 signals purifying selection.

Words worth knowing

TermWhat it means
Restriction endonucleaseA bacterial enzyme that cuts DNA at a specific, usually palindromic, recognition sequence.
Sticky endA short single stranded overhang left by a staggered cut that pairs with matching ends.
DNA ligaseThe enzyme that seals breaks in the DNA backbone by forming phosphodiester bonds.
VectorA DNA molecule, such as a plasmid, that carries a fragment into a host cell and replicates it.
Selectable markerA vector gene, such as antibiotic resistance, that lets only cells carrying the vector survive.
cDNADNA copied from mRNA by reverse transcriptase, lacking introns.
PCRPolymerase chain reaction; cycles of denaturing, annealing and extension that amplify a target exponentially.
PrimerA short oligonucleotide that pairs with a template and provides a 3′ end for polymerase.
Threshold cycleThe qPCR cycle at which fluorescence crosses a set level; lower values mean more starting template.
DideoxynucleotideA nucleotide lacking the 3′ hydroxyl, which ends DNA synthesis when incorporated.
Paired end readsSequence reads from both ends of the same fragment, a known distance apart.
CoverageThe average number of reads covering each base of a genome.
ContigA continuous stretch of sequence assembled from overlapping reads.
De novo assemblyBuilding a genome sequence from read overlaps without a reference.
CRISPR arrayBacterial repeats separated by spacers that record past infections.
Guide RNAThe RNA whose 20 nt spacer directs Cas9 to a matching DNA target.
PAMProtospacer adjacent motif; a short sequence (NGG for SpCas9) required next to the target.
NHEJNonhomologous end joining; direct rejoining of a break that often leaves small indels.
HDRHomology directed repair; repair copied from a homologous template such as a donor DNA.
Base editorA Cas9 nickase fused to a deaminase that changes one base without a double strand break.
C-value paradoxThe lack of correlation between genome size and organismal complexity.
Alu elementA primate SINE of about 300 bp with over a million copies in the human genome.
Open reading frameA stretch of codons from a start codon to a stop codon that could encode a protein.
AnnotationIdentifying genes and other functional elements in a genome sequence and assigning their roles.
RNA-seqSequencing cDNA made from RNA to measure transcript levels across the genome.
ChIP-seqSequencing DNA pulled down with an antibody to map where a protein or histone mark binds.
OrthologA homolog in another species separated from the gene by a speciation event.
ParalogA homolog in the same lineage separated from the gene by a duplication event.
SyntenyConservation of gene order along chromosomes between species.
dN/dSThe ratio of nonsynonymous to synonymous substitution rates, used to infer selection on a protein.
MetagenomicsSequencing DNA directly from an environmental or community sample.

Check yourself

About how often would a random 8 bp restriction site occur, and roughly how many sites would it have in a 3.1 Gb genome?
Once per 65,536 bp; about 47,000 sites. 48 = 65,536, and 3,100,000,000 ÷ 65,536 is about 47,300.
Why must PCR use a heat stable polymerase?
Every cycle heats the reaction to about 95 °C. An ordinary polymerase would be denatured in the first cycle; Taq from a hot spring bacterium survives repeated denaturation steps.
In qPCR, sample A reaches threshold at cycle 22 and sample B at cycle 25 (equal reference gene values). Which has more template, and how much more?
Sample A, about eightfold more. It crosses threshold 3 cycles earlier, and 23 = 8.
Why does a ddNTP stop DNA synthesis?
It lacks the 3′ hydroxyl. Polymerase forms each phosphodiester bond by attaching the next nucleotide to the 3′ OH of the chain, so a chain ending in a ddNTP cannot be extended.
Why do long reads give better assemblies than short reads, even at the same coverage?
They span repeats. A read longer than a repeat includes unique sequence on both sides, so the assembler knows which copy it came from; short reads within a repeat cannot be placed.
A guide RNA matches a 20 nt sequence that is followed by AAT, not NGG. Will SpCas9 cut it?
No. SpCas9 must recognize an NGG PAM immediately 3′ of the protospacer before it unwinds DNA, so a perfect guide match without a PAM is not cut.
Cas9 and a guide targeting an exon are introduced into cells with no donor. What outcomes do you expect, and what fraction disrupt the reading frame?
Mostly small indels from NHEJ; about two thirds are frameshifts. Indel lengths not divisible by 3 shift the frame, usually creating an early stop codon and a knockout.
How can the human genome be about 670 times the size of the E. coli genome but have only about five times as many protein coding genes?
Most human DNA is noncoding. Long introns, regulatory regions and repeats (about half the genome is transposable element sequence) account for the difference; only about 1.5 percent codes for protein.
Human myoglobin and human β-globin descend from an ancient duplication. Are they orthologs or paralogs?
Paralogs. They are related through a duplication within one lineage, not by speciation.
A gene compared between two primates has dN/dS = 2.5. What does this suggest?
Positive selection. Amino acid changes accumulated faster than silent changes, so changes in the protein were favored, as often seen in genes involved in immunity or reproduction.