📖 ContentsChapter 6
Genetics · Chapter 6

Chromosome Mutations

A single base change can alter one protein, but a chromosome mutation can add, remove or rearrange hundreds of genes at once. These large scale changes cause about half of early miscarriages, Down syndrome and many developmental disorders, drive certain leukemias, and built some of the most important crops on Earth. This chapter shows how chromosomes are described, how they break and rejoin, how whole chromosomes or whole sets are gained or lost, and what each change does in meiosis and in the clinic.

By the end of this chapter you can

  • Classify chromosomes by centromere position, describe telomeres and banding, and read standard karyotype notation.
  • Distinguish deletions, duplications, inversions and translocations, and explain how each pairs in meiosis.
  • Predict the products of a crossover within a paracentric or pericentric inversion loop.
  • Explain alternate and adjacent segregation in a reciprocal translocation heterozygote and the risks of a Robertsonian translocation.
  • Define aneuploidy terms and trace nondisjunction in meiosis I and meiosis II, using markers to tell which division failed.
  • Describe the major human aneuploidies, the maternal age effect, mosaicism and uniparental disomy.
  • Compare autopolyploidy and allopolyploidy, calculate gamete ratios in tetraploids and explain why triploids are sterile.
  • Relate microdeletion syndromes, cancer translocations such as the Philadelphia chromosome, and gene amplification to disease and therapy.

Section 1Chromosome structure and karyotypes

Parts of a chromosome

Every eukaryotic chromosome is one long DNA molecule packaged with proteins into chromatin. After replication, and until anaphase, each chromosome consists of two identical sister chromatids held together at the centromere. Three elements are essential for a chromosome to be copied and passed on faithfully:

The importance of these elements explains much of this chapter. A chromosome fragment with no centromere (acentric) cannot attach to the spindle and is lost at division. A chromosome with two centromeres (dicentric) may be pulled toward both poles and break. A broken end without a telomere is "sticky" and tends to fuse with other broken ends, which is how many rearrangements form.

Centromere position and chromosome shape

The centromere divides a chromosome into two arms. By convention the short arm is p (for petit) and the long arm is q. Chromosomes are classified by where the centromere lies, which is measured by the arm ratio (q length divided by p length) or the centromeric index (p length divided by total length).

TypeCentromere positionArm ratio q/p (approximate)Human examples
MetacentricNear the middle; arms about equal1.0 to 1.7Chromosomes 1, 3, 16, 19, 20
SubmetacentricOff center; clearly shorter p arm1.7 to 3.0Chromosomes 2, 4 to 12, 17, 18, X
AcrocentricVery near one end; tiny p arm, often with satellitesAbove 3.0Chromosomes 13, 14, 15, 21, 22 (and Y is nearly acrocentric)
TelocentricAt the very end; no p armNo p armNone in normal humans; common in mice

The tiny short arms of the five human acrocentric chromosomes carry the tandem ribosomal RNA genes, the nucleolus organizer regions. Because the same genes are repeated on all five, losing the short arms of two of them, as happens in a Robertsonian translocation, has no effect on the person.

MetacentricSubmetacentricAcrocentricTelocentric pqpqpqq centromere satellite (rRNA genes) p about equal to qp clearly shortertiny p armno p arm
Figure 6.1 Chromosome shapes by centromere (red) position, each drawn after replication with two sister chromatids. The short arm is p and the long arm is q. Human acrocentric chromosomes carry ribosomal RNA genes on their short arm satellites.

Making and reading a karyotype

A karyotype is the complete set of chromosomes of a cell, arranged in pairs by size, centromere position and banding pattern. Dividing cells (commonly cultured white blood cells, amniocytes or bone marrow) are treated with a spindle poison such as colchicine or colcemid, which arrests them in metaphase when chromosomes are most condensed. A hypotonic solution swells the cells, they are fixed and dropped onto slides, and the chromosomes are stained.

The standard stain is G-banding: a brief trypsin treatment followed by Giemsa dye. Dark G bands tend to be AT rich, gene poor and late replicating; light bands are GC rich and gene dense. Each chromosome has a reproducible pattern of about 400 to 550 bands per haploid set in a routine preparation, and up to about 850 in high resolution prometaphase spreads. Bands are numbered outward from the centromere: 7q31.2 means chromosome 7, long arm, region 3, band 1, sub-band 2.

A band at routine resolution contains roughly 5 to 10 Mb of DNA, so a G-banded karyotype detects gains, losses and rearrangements of about that size or larger. Molecular methods see far smaller changes:

Karyotype notation

The international system for human cytogenomic nomenclature (ISCN) writes the total chromosome number, then the sex chromosomes, then any abnormality. A normal female is 46,XX and a normal male 46,XY. A plus or minus sign before a chromosome number means a whole extra or missing chromosome. Structural changes use abbreviations followed by the chromosome(s) in one set of parentheses and the breakpoints in the next.

Study tip. Worked problem: Read each karyotype and say how many chromosomes the cell has and what is wrong. (a) 47,XY,+21. (b) 46,XX,del(5)(p15.2). (c) 45,XX,der(14;21)(q10;q10). (d) 46,XY,t(9;22)(q34;q11.2). Step 1, read (a): 47 chromosomes, male, an extra chromosome 21: trisomy 21, Down syndrome. Step 2, read (b): 46 chromosomes, female, a deletion of the short arm of chromosome 5 with its breakpoint in band p15.2, the cri du chat deletion. Step 3, read (c): 45 chromosomes, female, with a derivative chromosome made from the long arms of 14 and 21 (q10 is the centromere): a balanced Robertsonian translocation carrier with no missing genetic material of consequence. Step 4, read (d): 46 chromosomes, male, a reciprocal translocation between 9q34 and 22q11.2, the Philadelphia translocation of chronic myeloid leukemia. Answer: trisomy 21; 5p deletion; Robertsonian carrier; t(9;22). Second check, the arm ratio: a chromosome with p = 2.5 µm and q = 5.5 µm has q/p = 5.5/2.5 = 2.2 and centromeric index 2.5/8.0 = 0.31, so it is submetacentric.
Key point

A functional chromosome needs replication origins, one centromere and two telomeres. Chromosomes are described by centromere position (metacentric, submetacentric, acrocentric, telocentric) and by G-band patterns numbered from the centromere along the p and q arms. A banded karyotype sees changes of several megabases; FISH and chromosomal microarray detect much smaller changes, and ISCN notation records the result.

Section 2Deletions, duplications, inversions and translocations

How rearrangements arise

Structural rearrangements begin with double strand breaks, caused by ionizing radiation, some chemicals, replication errors or the cell's own programmed cuts. If the broken ends are rejoined wrongly, or if crossing over occurs between similar sequences at the wrong positions (nonallelic homologous recombination), the gene order changes. Repeated sequences, such as segmental duplications and transposable elements, are hotspots because they provide misleading homology.

RearrangementChange in gene order (normal: A B C • D E F G)Pairing in a heterozygoteMain genetic consequence
DeletionA B C • D G (E F lost)Unpaired loop on the normal homologLoss of genes; haploinsufficiency; pseudodominance
DuplicationA B C • D E F E F GUnpaired loop on the duplicated homologExtra dose of genes; raw material for new genes
Paracentric inversionA B C • D F E GInversion loop not including the centromereCrossover in loop gives dicentric and acentric products
Pericentric inversionA E D • C B F GInversion loop including the centromereCrossover in loop gives duplication plus deficiency products
Reciprocal translocationSegments exchanged between nonhomologous chromosomesCross shaped quadrivalentSemisterility; unbalanced gametes from adjacent segregation
Robertsonian translocationLong arms of two acrocentrics fusedTrivalent45 chromosomes; risk of trisomic offspring
NormalDeletionDuplicationInversionTranslocation A B C D E F G A B C D G A B C D E F E F G A B C D F E G A B C D E S P Q R F G E F missingE F repeated (gold)E F reversed (blue)F G swapped for Sfrom P Q R S chromosome
Figure 6.2 The four basic structural rearrangements, compared with a normal chromosome (red circle = centromere). The inversion shown is paracentric because the reversed segment does not include the centromere. In the reciprocal translocation, the ends of two nonhomologous chromosomes have been exchanged.

Deletions

A deletion (deficiency) removes a segment, either from the end (terminal) or from within (interstitial). In a deletion heterozygote, the normal homolog has nothing to pair with across the missing region, so it buckles out as a deletion loop during synapsis, visible in Drosophila polytene chromosomes. Two genetic effects reveal deletions. First, a deletion uncovers recessive alleles on the other homolog: a recessive allele opposite a deletion is expressed, a phenomenon called pseudodominance, which makes deletions excellent tools for mapping genes to small regions (just as Benzer used them in phage). Second, many genes are haploinsufficient: one copy does not make enough product for a normal phenotype. Large deletions are usually lethal when homozygous and often harmful when heterozygous. Deletion of part of the short arm of human chromosome 5 causes cri du chat syndrome, named for the high pitched, catlike cry of affected infants, together with intellectual disability and a small head.

Duplications

A duplication repeats a segment. In a tandem duplication the copies are adjacent and in the same orientation; in a reverse duplication they are in opposite orientation; a duplicated segment may also be inserted elsewhere. Duplications commonly arise by unequal crossing over between misaligned repeats, which creates a duplication on one chromatid and a reciprocal deletion on the other.

The Bar mutation of Drosophila is the classic case. Bar is a tandem duplication of a small region of the X chromosome that reduces the number of facets in the eye. Females with one Bar region on each X (B/B) have four copies of the region and small eyes, but females with a triple copy on one X and a single copy on the other (double Bar over wild type) also have four copies and even smaller eyes. Same dose, different phenotype: the arrangement mattered, an example of a position effect.

Duplications are also the raw material of evolution. Once a gene is duplicated, one copy can keep the original function while the other accumulates mutations and may gain a new role. The globin genes, olfactory receptor genes and Hox clusters are families that arose this way.

Connection. Charcot Marie Tooth disease type 1A, the most common inherited peripheral neuropathy, is caused by a 1.4 Mb duplication on chromosome 17p12 that gives three copies of the myelin gene PMP22. The reciprocal deletion of the same segment, leaving one copy, causes a different disorder, hereditary neuropathy with liability to pressure palsies. Both arise by unequal crossing over between flanking repeats, and together they show that gene dosage, not only gene sequence, matters for health.

Inversions

An inversion cuts out a segment and reinserts it in reverse. If the segment does not include the centromere, it is a paracentric inversion; if it does, it is a pericentric inversion, which can change the arm ratio and therefore the shape of the chromosome. An inversion homozygote usually has a normal phenotype, because no genes are lost or gained, unless a breakpoint disrupts a gene or moves it next to heterochromatin. The genetic action happens in heterozygotes. To pair gene for gene, one homolog must twist into an inversion loop.

A single crossover within the loop produces unbalanced chromatids:

In both cases the two nonrecombinant chromatids (one normal, one inverted) are balanced. Gametes carrying the unbalanced recombinant chromatids are inviable in plants or give inviable zygotes in animals, so recombinant progeny are not recovered for genes within the inversion. Inversions therefore act as crossover suppressors, keeping groups of alleles together. Geneticists exploit this in Drosophila balancer chromosomes, which carry multiple overlapping inversions, a dominant visible marker and a recessive lethal, to maintain a mutation in a stock without it being lost by recombination.

Crossover between B and C inside a paracentric inversion loop A B C D E A D C B E NormalInverted Shaded: the inverted segment B C D 1. Parental2. Parental3. Recombinant4. Recombinant A B C D E A D C B E A B C D A E D C B E balanced, normal order balanced, inverted order dicentric: forms a bridge, breaks acentric: no centromere, lost
Figure 6.3 A single crossover inside the loop of a paracentric inversion heterozygote. Only the two nonrecombinant chromatids are balanced; the dicentric and acentric recombinants lack genes, so recombinant offspring for genes in the inverted region are not recovered.
Study tip. Worked problem: A plant is heterozygous for a paracentric inversion. A single crossover occurs within the inversion loop in 30 percent of meioses; in the rest there is no crossover in the loop. What fraction of its pollen is unbalanced? Step 1, in a meiosis with one crossover in the loop, two of the four chromatids are recombinant (dicentric and acentric) and two are parental, so half the products are unbalanced. Step 2, in meioses without a loop crossover, all four products are balanced. Step 3, unbalanced fraction = 0.30 × 1/2 + 0.70 × 0 = 0.15. Answer: 15 percent of pollen is unbalanced and typically aborts, so the plant shows partial sterility, and no crossover offspring are recovered for genes inside the inversion. Common error: assuming all four products of a crossover meiosis are unbalanced; only the two chromatids that took part in the crossover are.

Translocations

A translocation moves a segment to a nonhomologous chromosome. In a reciprocal translocation, two nonhomologous chromosomes exchange segments. A carrier with a balanced reciprocal translocation has all its genes, usually in normal amounts, and is typically healthy. In meiosis, however, the two normal and two translocated chromosomes pair as a cross shaped quadrivalent, and how the four chromosomes segregate determines whether gametes are balanced:

Because adjacent and alternate segregation occur at similar frequencies in many plants, a translocation heterozygote is often semisterile, with about half its pollen or ovules aborted. In humans, balanced translocation carriers may have recurrent miscarriages or a child with an unbalanced karyotype. Translocations also produce pseudolinkage: genes near the breakpoints on the two different chromosomes behave as if linked, because only the alternate segregation products survive.

Robertsonian translocations

A Robertsonian translocation fuses the long arms of two acrocentric chromosomes at or near their centromeres, and the two tiny short arms are lost. The carrier has 45 chromosomes but is healthy, because the lost short arms carry only redundant ribosomal RNA genes. About 1 in 1,000 people carry one; rob(13;14) and rob(14;21) are the most common. The danger is to offspring.

Study tip. Worked problem: A woman has the karyotype 45,XX,der(14;21)(q10;q10). List the gametes she can produce and the outcomes when fertilized by a normal sperm. Step 1, the three chromosomes involved are a free 14, a free 21 and the fused 14/21. Segregation can produce six kinds of gametes: (1) 14 + 21; (2) der(14;21) alone; (3) der(14;21) + 21; (4) 14 alone; (5) der(14;21) + 14; (6) 21 alone. Step 2, add a normal sperm (one 14, one 21). (1) gives a normal child; (2) gives a balanced carrier like the mother; (3) gives three copies of 21q, translocation Down syndrome; (4) gives monosomy 21; (5) gives trisomy 14; (6) gives monosomy 14. Step 3, outcomes 4, 5 and 6 are lethal early in pregnancy, so only 1, 2 and 3 survive to birth. Answer: theoretically one in three liveborn children would have Down syndrome, but the observed risk is lower, about 10 to 15 percent when the mother is the carrier and under 5 percent when the father is, because unbalanced embryos and sperm are selected against. A carrier of der(21;21) can produce only gametes with two copies of 21q or none, so every viable pregnancy has Down syndrome.
Key point

Deletions remove genes, cause pseudodominance and reveal haploinsufficiency; duplications add dosage and fuel gene family evolution. Inversions are balanced but suppress recovery of recombinants because a crossover in the loop gives dicentric and acentric (paracentric) or duplication plus deficiency (pericentric) products. Reciprocal translocations cause semisterility through adjacent segregation, and Robertsonian translocations, though harmless to carriers, raise the risk of trisomic offspring.

Section 3Aneuploidy and nondisjunction

Terms for changes in chromosome number

Changes in chromosome number come in two kinds. Euploidy changes involve whole sets (the subject of Section 4). Aneuploidy is the gain or loss of individual chromosomes, so that the number is not an exact multiple of the haploid number. Using 2n for the normal diploid number:

Aneuploidy is usually far more harmful than polyploidy, even though it changes fewer genes. The reason is gene balance: many proteins work in complexes or pathways whose parts must be made in the right proportions. Adding a whole set keeps every ratio at 1:1; adding one chromosome raises the dose of hundreds of genes by 50 percent relative to all the others. In humans, every autosomal monosomy and most autosomal trisomies are lethal before birth.

Nondisjunction

Most aneuploidy arises from nondisjunction, the failure of chromosomes to separate properly. In meiosis I nondisjunction, a pair of homologs goes to the same pole; in meiosis II nondisjunction, a pair of sister chromatids goes to the same pole. The two produce different gamete sets:

That difference is the key to working out where nondisjunction occurred. If an extra chromosome carries two different alleles from one parent (both of that parent's homologs), the error was in meiosis I. If it carries two identical copies of one parental homolog, the error was most likely in meiosis II. (Crossing over complicates this for loci far from the centromere, so markers near the centromere give the cleanest answer.) Related mechanisms include anaphase lag, in which a chromosome is left behind and lost, and premature separation of sister chromatids in meiosis I.

Nondisjunction in meiosis I Nondisjunction in meiosis II errorerror n+1n+1n−1n−1 n+1n−1nn all four abnormal; n+1 has both homologs half abnormal; n+1 has identical sisters
Figure 6.4 Nondisjunction of one chromosome pair (blue and red homologs, each drawn as two sister chromatids before division). A meiosis I error puts both homologs into the same gametes; a meiosis II error puts two identical sister chromatids into one gamete and leaves the other two gametes normal.

Human aneuploidies

Only three autosomal trisomies commonly survive to birth, those of chromosomes 21, 18 and 13, which are among the most gene poor autosomes. Sex chromosome aneuploidies are far better tolerated, for two reasons: all X chromosomes beyond one are inactivated (Chapter 3), and the Y carries few genes.

ConditionKaryotypeApproximate frequency at birthMain features
Down syndrome47,+211 in 700Intellectual disability, characteristic facial features, heart defects (especially atrioventricular septal defect), hypotonia, increased leukemia and early Alzheimer disease risk
Edwards syndrome47,+181 in 5,000Growth restriction, clenched hands with overlapping fingers, rocker bottom feet, heart defects; most die in the first year
Patau syndrome47,+131 in 10,000 to 16,000Cleft lip and palate, polydactyly, holoprosencephaly, heart defects; most die in the first year
Turner syndrome45,X (about half of cases; others mosaic or structural)1 in 2,500 femalesShort stature, ovarian failure, webbed neck, coarctation of the aorta; normal intelligence
Klinefelter syndrome47,XXY1 in 500 to 1,000 malesTall stature, small testes, infertility, gynecomastia; often undiagnosed until adulthood
Triple X47,XXX1 in 1,000 femalesOften tall; usually fertile; mild learning differences in some
47,XYY47,XYY1 in 1,000 malesOften tall; usually fertile; mild learning differences in some

About 95 percent of Down syndrome is free trisomy 21, and in roughly 90 percent of these the extra chromosome comes from the mother, most often from a meiosis I error. About 3 to 4 percent of cases are due to a Robertsonian translocation (Section 2), which matters because it can recur in a family, and 1 to 2 percent are mosaic. The risk of free trisomy rises steeply with maternal age: approximately 1 in 1,250 births at age 25, 1 in 1,000 at 30, 1 in 350 at 35, 1 in 100 at 40 and 1 in 30 at 45. A leading explanation is that human oocytes begin meiosis I before birth and remain arrested for decades; the cohesin complexes that hold homologs and sisters together slowly deteriorate, and with fewer or poorly placed crossovers, homologs separate prematurely or not at all.

Study tip. Worked problem 1: A color blind boy has the karyotype 47,XXY. His mother has normal vision but is a heterozygous carrier (XAXa), and his father has normal vision (XAY). In which parent and in which meiotic division did nondisjunction occur? Step 1, a color blind XXY boy must be XaXaY, since any XA would give normal vision. Step 2, the father has no Xa, so both X chromosomes came from the mother and the Y came from the father. Step 3, the two maternal X chromosomes are identical (both Xa), so they are sister chromatids rather than both homologs. Answer: nondisjunction in the mother at meiosis II (assuming no crossover between the gene and the centromere). If he had been XAXaY with normal vision and both X's maternal, that would point to maternal meiosis I. Worked problem 2: a trisomic plant has genotype AAa. If any two of the three chromosomes go to one pole at random and the third to the other, what gametes form? Step 1, label the chromosomes A1, A2 and a. The three possible pairs are A1A2, A1a and A2a, each with probability 1/3, and the leftover single goes to the other pole. Step 2, this gives disomic gametes AA 1/6, Aa 2/6 and monosomic gametes a 1/6, A 2/6. Answer: 1 AA : 2 Aa : 2 A : 1 a. If all gametes function, selfing gives aa progeny only from a × a: (1/6)(1/6) = 1/36.

Mosaicism and uniparental disomy

Nondisjunction in a mitotic division after fertilization produces a mosaic, a person with two or more cell lines of different karyotype, such as 46,XX/47,XX,+21. Mosaics are usually more mildly affected than full trisomics, in proportion to how many cells, and which tissues, are abnormal. Mosaicism confined to the placenta can confuse prenatal tests that sample chorionic villi.

A trisomic embryo can sometimes "rescue" itself by losing one of the three copies in an early mitosis. If the lost copy is the one from the parent who contributed only one, the embryo ends up with both copies from the same parent, which is uniparental disomy (UPD). UPD is harmless for most chromosomes but causes disease when the region contains imprinted genes, or when the doubled chromosome carries a recessive mutation (isodisomy). Maternal UPD of chromosome 15 causes about a quarter of cases of Prader Willi syndrome, because the paternally expressed genes in 15q11-q13 are missing.

Key point

Aneuploidy adds or removes single chromosomes and disrupts gene balance, so it is usually severe. Nondisjunction in meiosis I puts both homologs into one gamete and leaves all four products abnormal; in meiosis II it puts two identical sisters together and leaves half normal. Only trisomies 13, 18 and 21 and the sex chromosome aneuploidies are common at birth; trisomy risk rises with maternal age, and mitotic errors give mosaics or uniparental disomy.

Section 4Polyploidy

Whole extra sets

Polyploids carry more than two complete chromosome sets. Geneticists use x for the number of chromosomes in one basic set and n for the number in a gamete. In a diploid these are the same, but in polyploids they differ. Bread wheat, for instance, is 2n = 6x = 42: each body cell has six sets of 7 chromosomes, and each gamete (n) has 21. Triploids (3x), tetraploids (4x), hexaploids (6x) and octoploids (8x) are all known.

Polyploidy is common in plants (most flowering plant lineages have undergone at least one whole genome duplication in their history) and in some fish, amphibians and insects, but rare in mammals. Plants tolerate it better for several reasons: many reproduce asexually or self fertilize, they lack chromosomal sex determination that would be upset by extra sets, and their development is more flexible. Polyploid plants often have larger cells and larger organs (fruits, flowers, leaves), the "gigas" effect, which made them attractive in agriculture.

Autopolyploidy

An autopolyploid has multiple sets from the same species. It can arise when a diploid gamete (from a failure of meiosis) fuses with a normal gamete, giving a triploid, or with another diploid gamete, giving a tetraploid. In the laboratory, colchicine, which binds tubulin and prevents spindle formation, blocks anaphase so that the chromosomes of a dividing cell are not separated, doubling the chromosome number in that cell and its descendants.

Autotetraploids are fertile but segregate in unusual ratios, because each chromosome has four homologs that can pair as a quadrivalent or as two bivalents, and any two of the four go to each gamete. Triploids are almost always highly sterile. With three homologs for each chromosome, one pole gets two and the other one, at random for each chromosome type. A gamete is balanced only if it receives exactly one copy of every chromosome (n = x) or two copies of every chromosome (2x). Seedless watermelons and the Cavendish banana (a triploid, 2n = 3x = 33) owe their seedlessness to this sterility.

Study tip. Worked problem 1: An autotetraploid has genotype AAaa at a locus near the centromere. Assume chromosomes pair at random and any two of the four go to each gamete. (a) What gametes form? (b) What is the phenotypic ratio after selfing if A is fully dominant? Step 1, label the chromosomes A1, A2, a1, a2. The number of ways to choose two of four is 4!/(2! 2!) = 6: A1A2, A1a1, A1a2, A2a1, A2a2, a1a2. Step 2, tally: AA 1, Aa 4, aa 1, so gametes are 1/6 AA, 4/6 Aa, 1/6 aa. Step 3, only aa × aa gives the recessive aaaa: (1/6)(1/6) = 1/36. Every other zygote has at least one A. Answer: gametes 1 AA : 4 Aa : 1 aa; phenotypes 35 dominant : 1 recessive, compared with 3:1 in a diploid. Worked problem 2: What fraction of gametes from a triploid with x = 11 are balanced? Step 1, for each of the 11 chromosome types, a given gamete receives one copy or two copies with probability 1/2 each. Step 2, P(all 11 are single) = (1/2)11 = 1/2,048, and P(all 11 are double) is also 1/2,048. Step 3, add them: 2/2,048 = 1/1,024. Answer: about 0.1 percent, which is why triploid bananas set essentially no seed.

Allopolyploidy

An allopolyploid combines chromosome sets from different species. A hybrid between two diploid species is usually sterile: its two sets are not homologous, so the chromosomes cannot pair and meiosis produces unbalanced gametes. If the hybrid's chromosome number doubles, however, every chromosome now has a partner, meiosis proceeds normally, and the result is a fertile amphidiploid (also called an allotetraploid). Because it cannot produce fertile offspring with either parent species, it is, in effect, a new species formed in a single generation.

The first deliberately made example was Georgii Karpechenko's 1928 cross of radish (Raphanus, 2n = 18) with cabbage (Brassica, 2n = 18). The F1 had 9 radish and 9 cabbage chromosomes and was sterile; a rare doubled form with 36 chromosomes was fertile. (Unfortunately for gardeners, it had the root of a cabbage and the leaves of a radish.)

RadishCabbage 2n = 18 (RR)2n = 18 (BB) gamete n = 9 (R)gamete n = 9 (B) F1 hybrid: 9 R + 9 B = 18 no partners in meiosis, sterile unpaired singles chromosome doubling (spontaneous or colchicine) Allotetraploid RRBB, 2n = 36 every chromosome paired, fertile bivalents form
Figure 6.5 Allopolyploidy in a radish by cabbage cross. The diploid hybrid is sterile because radish and cabbage chromosomes cannot pair; doubling gives each chromosome an identical partner, restoring normal meiosis and fertility and creating a new species in one step.

Polyploidy in crops and in animals

Many crops are polyploid, and their histories can be read in their genomes. Bread wheat (Triticum aestivum) arose from two hybridizations: a diploid AA wheat crossed with a BB goat grass to form tetraploid AABB (the ancestor of durum wheat), which later crossed with a third species, DD goat grass, giving hexaploid AABBDD. Plant breeders have made new allopolyploids too, such as triticale, a wheat by rye hybrid doubled with colchicine.

CropChromosome constitutionType
Banana (Cavendish)2n = 3x = 33Autotriploid, seedless
Seedless watermelon2n = 3x = 33, from a tetraploid by diploid crossAutotriploid, seedless
Potato (common)2n = 4x = 48Autotetraploid
Durum (pasta) wheat2n = 4x = 28, AABBAllotetraploid
Bread wheat2n = 6x = 42, AABBDDAllohexaploid
Upland cotton2n = 4x = 52Allotetraploid
Cultivated strawberry2n = 8x = 56Allooctoploid

In animals, whole genome duplication occurred twice early in vertebrate evolution, which is why we have four Hox clusters where an insect has one, and again in the ancestors of teleost fish and of salmon. Living polyploid animals include some frogs, lizards and fish, often reproducing asexually. In humans, triploidy (69 chromosomes) occurs in about 1 to 2 percent of conceptions, usually from fertilization of an egg by two sperm, and almost all are miscarried. Many human tissues contain endopolyploid cells, in which DNA has replicated without division: liver cells are often tetraploid, and megakaryocytes reach 16n or more. The giant polytene chromosomes of Drosophila salivary glands are an extreme case, with about 1,000 aligned copies of each chromatid, which makes deletions and inversions directly visible.

Key point

Polyploids carry extra whole sets, which preserves gene balance and is well tolerated in plants. Autopolyploids come from one species and show unusual segregation (35:1 after selfing AAaa) or, if triploid, near total sterility. Allopolyploids combine sets from two species; doubling a sterile hybrid gives a fertile new species, the origin of bread wheat, cotton and strawberries.

Section 5Chromosome mutations in human disease and cancer

How common are chromosome abnormalities?

Chromosome errors are strikingly common at conception and much rarer at birth, because most are lethal. About half of first trimester miscarriages are chromosomally abnormal. Among these, autosomal trisomies make up roughly half (trisomy 16, never seen at birth, is the single most common), followed by 45,X and triploidy. Among liveborn infants, about 1 in 150 (roughly 0.6 percent) has a chromosome abnormality, divided among aneuploidies, balanced rearrangements and unbalanced structural changes.

Microdeletion and microduplication syndromes

Some deletions are too small to see on a routine karyotype (under about 5 Mb) yet remove a group of neighboring genes, causing a recognizable contiguous gene syndrome. Many recur because they are flanked by low copy repeats that promote nonallelic homologous recombination; the same mechanism produces reciprocal duplications. They are diagnosed by FISH or chromosomal microarray.

SyndromeRegionKey gene(s)Main features
22q11.2 deletion (DiGeorge, velocardiofacial)22q11.2, about 3 MbTBX1Conotruncal heart defects, thymic hypoplasia with T cell deficiency, hypocalcemia from absent parathyroids, cleft palate, learning and psychiatric problems; about 1 in 4,000 births
Williams syndrome7q11.23ELN (elastin)Supravalvular aortic stenosis, hypercalcemia, very sociable personality, intellectual disability
Prader Willi / Angelman15q11-q13Imprinted genes (SNRPN cluster; UBE3A)Paternal deletion gives Prader Willi (hypotonia, then hyperphagia); maternal deletion gives Angelman (seizures, absent speech, happy demeanor)
Cri du chat5p15SeveralHigh pitched cry, microcephaly, intellectual disability
Wolf Hirschhorn4p16.3Several"Greek warrior helmet" facial appearance, seizures, growth delay
Smith Magenis17p11.2RAI1Sleep disturbance, self injurious behavior, intellectual disability

Chromosome changes in cancer

Cancer cells are genetically unstable, and chromosome mutations are among their most characteristic features. Most solid tumors are aneuploid, often with dozens of numerical and structural changes. But some cancers are driven by one specific rearrangement, and those have taught us how chromosome mutations activate genes. Rearrangements cause cancer in three main ways.

  1. Fusion genes. A translocation joins parts of two genes into a new gene encoding a hybrid protein with abnormal activity.
  2. Promoter or enhancer swapping. A translocation moves a proto-oncogene next to a strongly active regulatory region, so it is overexpressed even though its protein is normal.
  3. Copy number change. Amplification of an oncogene raises its dose, and deletion removes a tumor suppressor gene.

The first consistent cancer rearrangement found was the Philadelphia chromosome, a small chromosome 22 seen in about 95 percent of cases of chronic myeloid leukemia (CML). It results from the reciprocal translocation t(9;22)(q34;q11). The breakpoints fall within the ABL1 gene on 9q34 and the BCR gene on 22q11, and the derivative chromosome 22 carries a BCR-ABL1 fusion gene. Its protein is a tyrosine kinase that is always switched on, driving proliferation of myeloid cells. That discovery led to imatinib, a drug that blocks the ATP binding site of the BCR-ABL1 kinase and transformed CML from a fatal disease into a manageable one.

Before After t(9;22)(q34;q11) 922der(9)der(22) = Ph ABL1 BCR BCR-ABL1fusion q armp arm
Figure 6.6 The Philadelphia chromosome. In a reciprocal exchange between 9q34 and 22q11, the end of chromosome 9 carrying ABL1 (red band, blue segment) joins the BCR gene (green band) on chromosome 22. The shortened der(22), the Philadelphia chromosome, carries the BCR-ABL1 fusion gene whose constantly active kinase drives chronic myeloid leukemia.
RearrangementGenes involvedMechanismCancer and therapy note
t(9;22)(q34;q11)BCR-ABL1Fusion tyrosine kinaseChronic myeloid leukemia, some acute lymphoblastic leukemia; tyrosine kinase inhibitors such as imatinib
t(8;14)(q24;q32)MYC and immunoglobulin heavy chain (IGH)MYC overexpressed by immunoglobulin enhancerBurkitt lymphoma
t(14;18)(q32;q21)IGH and BCL2Antiapoptotic BCL2 overexpressedFollicular lymphoma
t(15;17)(q24;q21)PML-RARAFusion that blocks differentiationAcute promyelocytic leukemia; all trans retinoic acid and arsenic trioxide
t(11;22)(q24;q12)EWSR1-FLI1Fusion transcription factorEwing sarcoma
Amplification of 17q12ERBB2 (HER2)Increased copy number of a growth factor receptorAbout 15 to 20 percent of breast cancers; trastuzumab
Amplification of 2p24MYCNIncreased copy numberNeuroblastoma, marks a poor prognosis
Deletion of 13q14RB1Loss of a tumor suppressorRetinoblastoma

Amplified genes appear cytologically in two forms: double minutes, small paired acentric chromatin bodies, and homogeneously staining regions, long stretches of a chromosome that lack normal bands because they consist of repeated copies of the amplicon. Some tumors also show chromothripsis, in which one or a few chromosomes shatter into many pieces in a single catastrophic event and are stitched back together in random order.

Study tip. Worked problem: A dual color, dual fusion FISH test for CML uses a red probe spanning ABL1 on 9q34 and a green probe spanning BCR on 22q11. Breakage splits each probe, so a fusion appears as a red green (yellow) signal. Predict the signal pattern in (a) a normal interphase cell and (b) a cell with t(9;22). Step 1, a normal cell has two chromosome 9's and two 22's, each with one intact probe: 2 red, 2 green, 0 fusion. Step 2, in a t(9;22) cell, one 9 and one 22 are normal, giving 1 red and 1 green. Step 3, the translocated pair carries two fusions: der(22) has BCR-ABL1 and der(9) has the reciprocal ABL1-BCR junction, each showing red next to green. Answer: normal cells show 2R 2G; Philadelphia positive cells show 1R 1G 2F. Counting the fraction of 1R 1G 2F nuclei in a few hundred cells is how doctors track how well a patient responds to imatinib.
Connection. Knowing the exact chromosome change now chooses the treatment. A patient with acute promyelocytic leukemia confirmed to carry t(15;17) receives all trans retinoic acid and arsenic trioxide, which degrade the PML-RARA fusion protein and let the leukemic cells mature; cure rates exceed 90 percent. A breast tumor with ERBB2 amplification, detected by FISH or by protein staining, receives HER2 targeted antibodies. In each case a cytogenetic finding became a drug target.
Key point

Chromosome abnormalities are common in early pregnancy loss and occur in about 1 in 150 births. Small recurrent deletions mediated by flanking repeats cause contiguous gene syndromes such as 22q11.2 deletion and Williams syndrome. In cancer, translocations create fusion genes (BCR-ABL1, PML-RARA) or place oncogenes under strong enhancers (MYC in Burkitt lymphoma), amplification raises oncogene dose and deletion removes tumor suppressors, and each of these changes can guide diagnosis and therapy.

The chapter in one breath

  • A working chromosome needs replication origins, one centromere and two telomeres; acentric fragments are lost and dicentrics break.
  • Chromosomes are metacentric, submetacentric, acrocentric or telocentric, and G-bands are numbered outward from the centromere on the p and q arms.
  • A banded karyotype sees changes of several megabases; FISH and chromosomal microarray detect much smaller ones, but a microarray misses balanced rearrangements.
  • Deletions cause pseudodominance and haploinsufficiency; duplications add dose and arise by unequal crossing over.
  • A crossover within a paracentric inversion loop gives a dicentric bridge and an acentric fragment; within a pericentric inversion it gives duplication plus deficiency products, so inversions suppress recombinant offspring.
  • Reciprocal translocation heterozygotes form quadrivalents; adjacent segregation gives unbalanced gametes and semisterility.
  • Robertsonian translocation carriers have 45 chromosomes and are healthy but can have children with translocation Down syndrome.
  • Nondisjunction in meiosis I makes all four gametes abnormal; in meiosis II, half; markers near the centromere reveal which division failed.
  • Trisomies 21, 18 and 13 and the sex chromosome aneuploidies survive to birth; trisomy risk rises with maternal age.
  • Autopolyploids segregate in odd ratios and triploids are nearly sterile; allopolyploids formed by doubling a hybrid are fertile new species such as bread wheat.
  • Cancer rearrangements create fusion genes such as BCR-ABL1, drive oncogenes with strong enhancers, amplify oncogenes and delete tumor suppressors.

Words worth knowing

TermWhat it means
CentromereThe constricted region where sister chromatids are joined and the kinetochore attaches to the spindle.
TelomereThe repeated DNA and protein cap at each chromosome end that prevents end fusion.
AcrocentricA chromosome with its centromere very close to one end, giving a tiny short arm.
KaryotypeThe complete chromosome set of a cell, arranged in pairs by size, shape and banding.
G-bandingTrypsin plus Giemsa staining that gives each chromosome a reproducible pattern of light and dark bands.
FISHFluorescence in situ hybridization: locating a DNA sequence on chromosomes or in nuclei with a fluorescent probe.
Chromosomal microarrayA genome wide test that detects gains and losses of DNA (copy number variants) as small as tens of kilobases.
DeletionLoss of a chromosome segment.
PseudodominanceExpression of a recessive allele because the homologous region on the other chromosome is deleted.
HaploinsufficiencyA situation in which one working copy of a gene does not give a normal phenotype.
DuplicationRepetition of a chromosome segment.
Unequal crossing overCrossing over between misaligned repeats, producing a duplication and a reciprocal deletion.
Position effectA change in gene expression caused by a change in a gene's chromosomal location or arrangement.
Paracentric inversionAn inversion that does not include the centromere.
Pericentric inversionAn inversion that includes the centromere.
Dicentric bridgeA chromatid with two centromeres stretched between the poles at anaphase.
Reciprocal translocationExchange of segments between two nonhomologous chromosomes.
Adjacent segregationSegregation from a translocation quadrivalent that gives gametes with a duplication and a deficiency.
Robertsonian translocationFusion of the long arms of two acrocentric chromosomes, leaving 45 chromosomes.
AneuploidyGain or loss of one or a few chromosomes rather than whole sets.
NondisjunctionFailure of homologs (meiosis I) or sister chromatids (meiosis II or mitosis) to separate.
TrisomyPresence of three copies of one chromosome (2n + 1).
MonosomyPresence of only one copy of a chromosome (2n − 1).
MosaicismPresence of two or more genetically different cell lines in one individual.
Uniparental disomyInheritance of both copies of a chromosome from the same parent.
PolyploidyPossession of more than two complete chromosome sets.
AutopolyploidA polyploid whose sets all come from one species.
AllopolyploidA polyploid that combines chromosome sets from different species.
ColchicineA drug that blocks spindle formation, used to arrest cells in metaphase and to double chromosome number.
Philadelphia chromosomeThe shortened chromosome 22 from t(9;22) that carries the BCR-ABL1 fusion gene.
Gene amplificationAn increase in the number of copies of a chromosome region, often containing an oncogene.
Microdeletion syndromeA disorder caused by a deletion too small to see on a routine karyotype that removes several adjacent genes.

Check yourself

A chromosome has a p arm of 1.5 µm and a q arm of 7.5 µm. Calculate the arm ratio and classify it.
Answer. q/p = 7.5/1.5 = 5.0, well above 3.0, so it is acrocentric. Its centromeric index is 1.5/9.0 = 0.17.
Why can a chromosomal microarray miss a balanced reciprocal translocation that a karyotype detects?
Answer. A microarray measures how much DNA is present at each position, not where it is. A balanced translocation moves segments without gain or loss, so copy number is unchanged, while a karyotype shows the altered banding pattern.
A fly heterozygous for a deletion shows a recessive mutant phenotype for one gene but not for a nearby gene. What can you conclude?
Answer. The first gene lies within the deleted region (pseudodominance: the recessive allele on the intact homolog has no partner), and the second lies outside it.
Why does a crossover within a pericentric inversion loop not produce a dicentric bridge?
Answer. The centromere lies inside the inverted segment, so each recombinant chromatid ends up with one centromere. Instead, each carries a duplication of one end and a deficiency of the other.
A plant heterozygous for a reciprocal translocation has about 50 percent pollen abortion. Explain why.
Answer. The four chromosomes pair as a quadrivalent. Alternate segregation gives balanced gametes, but adjacent-1 (and rarely adjacent-2) segregation gives gametes with duplications and deficiencies. When alternate and adjacent segregation are about equally frequent, roughly half the pollen is unbalanced and aborts: semisterility.
A child has Down syndrome with 46 chromosomes. What is the likely karyotype, and why should the parents be karyotyped?
Answer. Translocation Down syndrome, for example 46,XX,der(14;21)(q10;q10),+21 (two free 21's plus a 14/21 fusion). One parent may be a balanced Robertsonian carrier with a substantial recurrence risk, unlike free trisomy 21.
A trisomy 21 child has two different chromosome 21 marker alleles (near the centromere) from the mother and one from the father. Where did nondisjunction occur?
Answer. In maternal meiosis I. Two different maternal alleles means both maternal homologs were passed on together, which happens when homologs fail to separate in the first division.
Why are autosomal monosomies lethal in humans while 45,X is often compatible with life?
Answer. Losing an autosome halves the dose of hundreds of genes and is lethal. Normally all but one X is inactivated anyway, so a single X provides most of the needed dosage; 45,X is still lethal in most conceptions, and survivors have Turner syndrome partly because a few X genes escape inactivation.
An autotetraploid AAAa is selfed. What fraction of progeny show the recessive phenotype, assuming chromosome segregation?
Answer. None. Choosing two of four chromosomes gives AA (3 of 6 ways) or Aa (3 of 6), so gametes are 1/2 AA and 1/2 Aa. No gamete is aa, so no aaaa progeny can form.
Why did the discovery that CML is driven by BCR-ABL1 lead directly to a targeted drug?
Answer. The translocation creates a single fusion protein, a constantly active tyrosine kinase, that the leukemic cells depend on. A small molecule (imatinib) that blocks its ATP binding site shuts down the driver while largely sparing normal cells.